Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
a | 534 | 20 | 1 | 20.0000 |
który | 206 | 8 | 1 | 8.0000 |
ma | 156 | 7 | 1 | 7.0000 |
ale | 151 | 7 | 1 | 7.0000 |
które | 166 | 7 | 1 | 7.0000 |
która | 109 | 5 | 1 | 5.0000 |
przy | 156 | 10 | 2 | 5.0000 |
ta | 69 | 5 | 1 | 5.0000 |
we | 92 | 10 | 2 | 5.0000 |
m | 37 | 5 | 1 | 5.0000 |
25 | 40 | 4 | 1 | 4.0000 |
zakończył | 32 | 4 | 1 | 4.0000 |
26 | 23 | 4 | 1 | 4.0000 |
były | 123 | 4 | 1 | 4.0000 |
swoją | 55 | 4 | 1 | 4.0000 |
co | 159 | 11 | 3 | 3.6667 |
20 | 54 | 7 | 2 | 3.5000 |
5 | 77 | 7 | 2 | 3.5000 |
że | 423 | 9 | 3 | 3.0000 |
cm | 36 | 3 | 1 | 3.0000 |
Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
października | 53 | 1 | 8 | 0.1250 |
lata | 72 | 1 | 7 | 0.1429 |
dwóch | 76 | 1 | 6 | 0.1667 |
także | 268 | 1 | 6 | 0.1667 |
pierwszym | 49 | 1 | 6 | 0.1667 |
wieku | 167 | 2 | 12 | 0.1667 |
września | 80 | 2 | 11 | 0.1818 |
też | 145 | 2 | 11 | 0.1818 |
w. | 36 | 1 | 5 | 0.2000 |
którym | 82 | 1 | 5 | 0.2000 |
nim | 82 | 1 | 5 | 0.2000 |
ona | 52 | 1 | 5 | 0.2000 |
udział | 64 | 1 | 5 | 0.2000 |
jeden | 59 | 1 | 5 | 0.2000 |
końca | 40 | 1 | 5 | 0.2000 |
siebie | 36 | 1 | 5 | 0.2000 |
sezonie | 52 | 1 | 5 | 0.2000 |
listopada | 38 | 1 | 5 | 0.2000 |
życia | 78 | 1 | 5 | 0.2000 |
lutego | 37 | 1 | 5 | 0.2000 |
In this subsection, we compute the ratio of the number of right neighbors and the number of left neighbors. Again, we look for words with extreme ratios:
Data for first table:
select word,w.freq,aa.cnt, bb.cnt,aa.cnt/bb.cnt as r from words w, (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where w_id=aa.w1_id and aa.w1_id=bb.w2_id order by r desc limit 20;
Diagram data:
select aa.cnt, bb.cnt from (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where aa.w1_id=bb.w2_id;
5.1.7.1 Number of NN co-occurrences vs. Frequency I
5.1.7.2 Number of NN co-occurrences vs. Frequency II